A wire carries a current of 4A. What is the magnetic field 5 cm away from it?
Solution:
\(B= \frac{4π \times 10^{-7} \times 4}{2π \times 0.05} = 1.6 \times 10^{-5} \: \text{T}\)
In this lesson, we will discuss the induced magnetic field due to a wire, a loop, and a solenoid (coil of wires with many turns). Any wire with a current running through it induces a magnetic field. We can quantify the magnitude of the magnetic field due to a wire using the formula below.
\[B= \frac{\mu _0 I}{2πr}\]
Where:
And for a loop, we can quantify the magnetic field at its center using the formula
\[B= \frac{\mu _0 I}{2R}\]
Where R is the radius of the loop.
And finally, for an ideal solenoid at its center, the magnetic field can be quantified with the formula
\[B =\mu _0 nI\]
Where n is the number of turns per unit length of the solenoid.
A wire carries a current of 4A. What is the magnetic field 5 cm away from it?
Solution:
\(B= \frac{4π \times 10^{-7} \times 4}{2π \times 0.05} = 1.6 \times 10^{-5} \: \text{T}\)
What is the magnetic field at the center of a circular loop of radius 10 cm carrying a current of 3 A?
Solution:
\(B= \frac{4 \mu \times 10^{-7} \times 3}{2 \times 0.1} = 1.88 \times 10^{-5} \: \text{T}\)
Written by Mubarak Aouda